1.若/x+y-5/+(xy-4)²=0,求x²+y²【/ /為絕對(duì)值符號(hào)】
1.若/x+y-5/+(xy-4)²=0,求x²+y²【/ /為絕對(duì)值符號(hào)】
2.若已知a+b+10,a²+b²=4,求ab的值
3.若x-2y=15,xy=-10,求x²+4y²+1的值
2.若已知a+b+10,a²+b²=4,求ab的值
3.若x-2y=15,xy=-10,求x²+4y²+1的值
數(shù)學(xué)人氣：641 ℃時(shí)間：2020-08-23 09:52:24
優(yōu)質(zhì)解答
1、依題意可得x+y-5=0,即x+y=5xy-4=0,即xy=4x²+y²=(x+y)²-2xy=5²-2*4=172、a+b=0,得（a+b)²=100即a²+b²+2ab=100又a²+b²=4,所以2ab=100-4即ab=483、x²+4y²+1...
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