(2)根據(jù)題意,得:y≥2x,
∴150-x≥2x,解得:x≤50,
又∵x≥0,150-x≥0,
∴0≤x≤50(5分),
∴p=600x+1000(150-x),
=-400x+150000.(6分)
(法一)∵x=
150000?p |
400 |
∴0≤
150000?p |
400 |
解得:130000≤p≤150000.
(法二)又∵p隨x的增大而減小,并且0≤x≤50,
∴-400×50+150000≤p≤-400×0+150000,即130000≤p≤150000.
150000?p |
400 |
150000?p |
400 |