x^3+y^3+z^3-3xyz
= (x+y)(x^2+y^2-xy)+z^3-3xyz
= (x+y)[(x+y)^2-3xy]+z^3-3xyz
= (x+y)^3-3xy(x+y)+z^3-3xyz
= (x+y)^3+z^3-3xy(x+y)-3xyz
= (x+y+z)[(x+y)^2+z^2-z(x+y)]-[3xy(x+y)+3xyz]
= (x+y+z)(x^2+y^2+2xy+z^2-xz-yz)-3xy(x+y+z)
= (x+y+z)(x^2+y^2+z^2-xy-xz-yz)
x^3+y^3+z^3 -3xyz 這個(gè)怎么分解因式
x^3+y^3+z^3 -3xyz 這個(gè)怎么分解因式
我知道答案是(x+y+z)(x^2+y^2+z^2-xy-xz-yz)
如果有特殊的數(shù)學(xué)符號我看不懂請備注一下
我知道答案是(x+y+z)(x^2+y^2+z^2-xy-xz-yz)
如果有特殊的數(shù)學(xué)符號我看不懂請備注一下
數(shù)學(xué)人氣:267 ℃時(shí)間:2020-04-01 09:40:25
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