(3ab^2）/(2cd）*(4c^2d^3)/（3a^2b^4)
= (3ab^2*4c^2d^3）/(2cd*3a^2b^4)
＝(2cd^2)/(ab^2)
3ab^2/2cd*4c^2d^3/3a^2b^4=
3ab^2/2cd*4c^2d^3/3a^2b^4=
數(shù)學(xué)人氣：521 ℃時間：2020-06-21 09:25:52
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