設(shè)其為 A_n
由題有：
A_4 - A_2 = 4; A_6 -A_4 = 8; ==>
A_2*n+2 -A_2*n = 4*2^(n-1) ===>
A_2*n = 4*(2^n -1); n = 1,2,3.
A_3 - A_1 = 3 - 1 = 2 = 1+1 = 1^2 +1;
A_5 - A_3 = 13 - 3 = 10 = 9+1 = 3^2 +1;
A_7 - A_5 = 39 - 13 = 26 = 25+1 = 5^2 +1; ==>
A_2*n+1 - A_2*n-1 = (2*n - 1)^2 +1; ==>
A_2n+1 = n + 1 + n*(4*n^2-1)/3; n = 0,1,2.
綜上知A_n為：
當(dāng) n 為偶數(shù)時(shí).
當(dāng) n 為奇數(shù)時(shí).