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  • 計(jì)算:1/(x-1)(x-2)+1/(x-2)(x-3)+1/(x-3)(x-4)+……+1/(x-2010)(x-2011)

    計(jì)算:1/(x-1)(x-2)+1/(x-2)(x-3)+1/(x-3)(x-4)+……+1/(x-2010)(x-2011)
    數(shù)學(xué)人氣:530 ℃時(shí)間:2019-11-04 12:33:19
    優(yōu)質(zhì)解答
    1/(x-1)(x-2)+1/(x-2)(x-3)+1/(x-3)(x-4)+……+1/(x-2010)(x-2011)
    =1/(x-2)-1/(x-1)+1/(x-3)-1/(x-2)+1/(x-4)-1/(x-3)+.+1/(x-2011)-1/(x-2010)
    =1/(x-2011)-1/(x-1)
    =2010/[(x-2011)(x-1)]您確定一定以及肯定是對(duì)的?對(duì)的如果對(duì)我會(huì)加分!肯定對(duì)的
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