答:
5sinα=3sin(α-2β)
5sin[(α-β)+β]=3sin[(α-β)-β]
5sin(α-β)coaβ+5cos(α-β)sinβ=3sin(α-β)cosβ-3cos(α-β)sinβ
2sin(α-β)cosβ=-8cos(α-β)sinβ
兩邊同除以cos(α-β)cosβ,
2tan(α-β)=-8tanβ
tan(α-β)+4tanβ=0.
5sina=3sin(a-2β)求證tan(a-β)+4tanβ=0
5sina=3sin(a-2β)求證tan(a-β)+4tanβ=0
數(shù)學(xué)人氣：745 ℃時(shí)間：2020-06-18 11:24:43
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