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  • 找規(guī)律計算:1/x(x+2)+1/(x+2)(x+4)+1/(x+4)(x+6)+……1/(x+2004)(x+2006)

    找規(guī)律計算:1/x(x+2)+1/(x+2)(x+4)+1/(x+4)(x+6)+……1/(x+2004)(x+2006)
    數(shù)學(xué)人氣:579 ℃時間:2019-11-04 04:39:45
    優(yōu)質(zhì)解答
    1/x(x+2)+1/(x+2)(x+4)+1/(x+4)(x+6)+……1/(x+2004)(x+2006)
    =1/2[1/x-1/(x+2)]+1/2[1/(x+2)-1/(x+4)]+1/2[1/(x+4)-1/(x+6)]+……+1/2[1/(x+2004)-1/(x+2006)]
    =1/2[1/x-1/(x+2)+1/(x+2)-1/(x+4)+1/(x+4)-1/(x+6)+……+1/(x+2004)-1/(x+2006)]
    =1/2[1/x-1/(x+2006)]
    =1003/x(x+2006)
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