:(-2a/b^2)^2*(b^3/4a^
=4a²/b^4×b³/4a²
=1/b
計(jì)算：(x+3/x^2-3x-x-1/x^2-6x+9)/x-9/x的值
原式=[(x+3)(x-3)/x(x-3)²-x(x-1)/x(x-3)²]÷x/(x-9)
=(x²-9-x²+x)/x(x-3)²×x/(x-9)
=(x-9)/x(x-3)²×x/(x-9)
=1/(x-3)²那個(gè)，對不起，第一題我打錯(cuò)啦==改為計(jì)算:(-2a/b^2)^2*(b^3/4a^ 4)^3:(-2a/b^2)^2*(b^3/4a^ 4)^3=4a²/b^4×b^9/64a^12=b^5/16a^10