解法1.找兩個(gè)關(guān)于直線x=π/3對(duì)稱的點(diǎn),代入函數(shù),看y是否相等
如點(diǎn)(0,y1)和(2π/3,y2)
(-2π/3,y1),(4π/3,y2)
看y1是否等于y2
答案有錯(cuò)
下列函數(shù)中,周期為π,圖像關(guān)于直線x=π/3對(duì)稱的函數(shù)是( )
下列函數(shù)中,周期為π,圖像關(guān)于直線x=π/3對(duì)稱的函數(shù)是( )
A.y=2sin(x/2+π/3)
B.y=2sin(x/2-π/3)
C.y=2sin(2x+π/6)
D.y=2sin(2x-π/3)
答案上先用定義排除AB,周期為π,AB不成立.
然后,又∵x=π/3為對(duì)稱軸,
由C項(xiàng),我們可取點(diǎn)(0,-1/2)關(guān)于x=π/3的對(duì)稱點(diǎn)(2π/3,-1/2),將x=2π/3代入C項(xiàng),則y=-2≠-1/2.故選D項(xiàng).
疑問!
Q:為什么取點(diǎn)(0,-1/2),C項(xiàng)中當(dāng)x=0時(shí)y不應(yīng)該=-1嗎?
A.y=2sin(x/2+π/3)
B.y=2sin(x/2-π/3)
C.y=2sin(2x+π/6)
D.y=2sin(2x-π/3)
答案上先用定義排除AB,周期為π,AB不成立.
然后,又∵x=π/3為對(duì)稱軸,
由C項(xiàng),我們可取點(diǎn)(0,-1/2)關(guān)于x=π/3的對(duì)稱點(diǎn)(2π/3,-1/2),將x=2π/3代入C項(xiàng),則y=-2≠-1/2.故選D項(xiàng).
疑問!
Q:為什么取點(diǎn)(0,-1/2),C項(xiàng)中當(dāng)x=0時(shí)y不應(yīng)該=-1嗎?
數(shù)學(xué)人氣:369 ℃時(shí)間:2019-12-15 10:59:45
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