已知等比數(shù)列an為遞增數(shù)列,且A5²＝A10,2(An+An+2)＝5An+1.n屬于N＊.⑴令Cn=1-...
已知等比數(shù)列an為遞增數(shù)列,且A5²＝A10,2(An+An+2)＝5An+1.n屬于N＊.⑴令Cn=1-(-1)∧n×an,不等式Ck≥2014(1≤k≤100,k∈N*)的解集為M求所有dk+ak(k∈M)的和. 哪位大神幫幫忙,我算了半天,才算出an的通項(xiàng)公式為an＝2∧n
D(k)是一個(gè)數(shù)列