找y'x
然后y'x是slope,因為normal垂直perpendicular,所以y1 times y2 equal to -1,
then find the value of y2(the normal one),
然后再代入隨便一個數(shù)到原始y 得出(x,y)坐標(biāo),代入y2(normal)得出
find an equation for a line that is normal to the graph of y = xe^x and goes
find an equation for a line that is normal to the graph of y = xe^x and goes
其他人氣:254 ℃時間:2020-04-04 02:58:24
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