0a^x是減函數(shù)
則2x²-3x+2<2x²+2x-3
x>1
a>1
a^x是增函數(shù)
則2x²-3x+2>2x²+2x-3
x<1
解a^(2x^2-3x+2)>a^(2x^2+2x-3) ——a>0,a不等于1
解a^(2x^2-3x+2)>a^(2x^2+2x-3) ——a>0,a不等于1
數(shù)學(xué)人氣:107 ℃時間:2020-06-19 18:07:44
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