若多項(xiàng)式2x^2+ax-y+b-(2bx^2-3x+5y-1)中不含x^2和x的項(xiàng),則a=?b=?
若多項(xiàng)式2x^2+ax-y+b-(2bx^2-3x+5y-1)中不含x^2和x的項(xiàng),則a=?b=?
數(shù)學(xué)人氣：155 ℃時(shí)間：2019-08-19 02:59:53
優(yōu)質(zhì)解答
a=-3 b = 1過程？2x^2+ax-y+b-(2bx^2-3x+5y-1)=(2-2b)x^2+(a+3)x-y+b-5y+1要不含x^2和x需2-2b=0a+3 = 0所以a=-3 b = 12-2b怎樣得的？2x^2+ax-y+b-(2bx^2-3x+5y-1)=2x^2+ax-y+b-2bx^2+3x-5y+1(把后面的括號(hào)打開就可以了)=(2-2b)x^2+(a+3)x-y+b-5y+1
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