若x+5<=0.且2x+1<=0,則x<-=5,所以當(dāng)x<-=5時,有-(x+5)<-(2x+1),得x<4
當(dāng)-5
含絕對值的不等式怎么解?
含絕對值的不等式怎么解?
X+5的絕對值小于2X+1怎么解
X+5的絕對值小于2X+1怎么解
數(shù)學(xué)人氣：958 ℃時間：2020-02-02 17:24:52
優(yōu)質(zhì)解答
若x+5>=0.且2x+1>=0,則x>=-1/2,所以當(dāng)x>=-1/2時,有x+5<2x+1,得x>4
若x+5<=0.且2x+1<=0,則x<-=5,所以當(dāng)x<-=5時,有-(x+5)<-(2x+1),得x<4
當(dāng)-5
若x+5<=0.且2x+1<=0,則x<-=5,所以當(dāng)x<-=5時,有-(x+5)<-(2x+1),得x<4
當(dāng)-5
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