可以用歸納法
T1=S1`2
設(shè)n=k 時(shí)成立
n=k+1
T（k+1）=Tk+（k+1）`3=Sk`2+(k+1)`3
S(k+1)`2=(Sk+k+1)`2
=Sk`2+2(k+1)Sk+(k+1)`2
=Sk`2+2(K+1)(k+1)k/2+(k+1)`2 注：Sn=（n+1）n/2
=Sk`2+k(k+1)`2+(k+1)`2
=Sk`2+(k+1)`3
=T（k+1）
已知數(shù)列an=n,前n項(xiàng)和為Sn,bn=n³,前n項(xiàng)和為Tn,求證Tn=Sn²
已知數(shù)列an=n,前n項(xiàng)和為Sn,bn=n³,前n項(xiàng)和為Tn,求證Tn=Sn²
數(shù)學(xué)人氣：813 ℃時(shí)間：2020-09-29 18:57:27
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