(-2^x2^y)^3+8(x^2)^2×(-x^2) ×(-y^3)
=-2^(3x+3y)+8x^6y^3
=-8^(x+y)+8x^6y^3
(-2^x2^y)^3+8(x^2)^2×(-x^2) ×(-y^3)
(-2^x2^y)^3+8(x^2)^2×(-x^2) ×(-y^3)
(-2^x2^y)^3+8(x^2)^2*(-2^2)*(-y^3)=?
(-2^x2^y)^3+8(x^2)^2*(-2^2)*(-y^3)=?
數(shù)學(xué)人氣:210 ℃時間:2020-07-15 16:36:48
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