若(a-2)的平方-(b-3)的平方=6,a,b互為相反數(shù),求a平方+b平方的值
(a-2)^2-(b-3)^2=6,b=-a
a^2-4a+4-(-a-3)^2=6
a^2-4a+4-(a^2+6a+9)=6
-10a=11
a=-11/10
b=11/10
a^2+b^2=121/100+121/100=121/50（x+1）平方=5，且2mx平方+4mx-12=0，求2m平方+m會(huì)追加分（x+1）^2=5
x=-1±√5
mx^2+2mx-6=0
x=-1+√5
m(6-2√5)+2m(-1+√5)-6=0
4m=6,m=3/2
2m^2+m=6
x=-1-√5
m(6+2√5)+2m(-1-√5)-6=0
4m=6,m=3/2
2m^2+m=6