不等式log1/3為底(x²-5x+7)>0的解集為什么?
不等式log1/3為底(x²-5x+7)>0的解集為什么?
數(shù)學人氣:756 ℃時間:2019-10-19 17:58:30
優(yōu)質(zhì)解答
//-----------------------------------------分割線----------------------------------------------------------------log1/3(x²-5x+7)>0=log1/3(1)易知y=log1/3(x)在(0,+∞)上單調(diào)遞減令f(x)=x²-5x+7,...
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