多項(xiàng)式7 .?然后呢?
是：當(dāng)a=0.35,B=-0.28時(shí),求多項(xiàng)式7a^3-6a^3b+3a^2b+3a^3+6a^3b-3a^2b-10a^3+3,題中有一個條件是多余的嗎?
7a^3-6a^3b+3a^2b+3a^3+6a^3b-3a^2b-10a^3+3
=(7a^3+3a^3-10a^3)+(-6a^3b+6a^3b)+(3a^2b-3a^2b)+3
=0+0+0+3
=3
所以a和b的值是多余的