對(duì)于函數(shù)f(x),若存在x0∈R,使得f(x0)=x0成立,則稱(chēng)x0為f(x)的天宮一號(hào)點(diǎn).已知函數(shù)f(x)=ax2+(b-7)x+18的兩個(gè)天宮一號(hào)點(diǎn)分別是-3和2. (1)求a,b的值及f(x)的表達(dá)式; (2)當(dāng)函
對(duì)于函數(shù)f(x),若存在x0∈R,使得f(x0)=x0成立,則稱(chēng)x0為f(x)的天宮一號(hào)點(diǎn).已知函數(shù)f(x)=ax2+(b-7)x+18的兩個(gè)天宮一號(hào)點(diǎn)分別是-3和2.
(1)求a,b的值及f(x)的表達(dá)式;
(2)當(dāng)函數(shù)f(x)的定義域是[t,t+1](t>0)時(shí),f(x)的最大值為G(t),最小值為g(t),求H(t)=G(t)-g(t)的表示式.
(1)求a,b的值及f(x)的表達(dá)式;
(2)當(dāng)函數(shù)f(x)的定義域是[t,t+1](t>0)時(shí),f(x)的最大值為G(t),最小值為g(t),求H(t)=G(t)-g(t)的表示式.
數(shù)學(xué)人氣:164 ℃時(shí)間:2019-10-25 23:26:30
優(yōu)質(zhì)解答
(1)依題意得f(-3)=-3,f(2)=2;即9a+21-3b+18=-3,4a+2b-14+18=2,解得a=-3,b=5∴f(x)=-3x2-2x+18(2)∵f(x)對(duì)稱(chēng)軸為 x=?13<0∴f(x)在[t,t+1](t>0)內(nèi)是單調(diào)減函數(shù),G(t)=f(x)max=f(t)=...
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