y=(x-1)^2
x=1時y=0
y=0 時x=1,
則y與x的交點為(1,0)
則X≤1時,Y單調(diào)減少,單減區(qū)間(-∞,1]
求y=x^-2x+1的單減區(qū)間
求y=x^-2x+1的單減區(qū)間
數(shù)學(xué)人氣：546 ℃時間：2020-05-13 18:52:31
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