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  • cosπ/11*cos2π/11*cos3π/11*cos4π/11*cos5π/11

    cosπ/11*cos2π/11*cos3π/11*cos4π/11*cos5π/11
    上式為何等于cosπ/11*cos2π/11*cos4π/11*cos8π/11*cos16π/11
    數(shù)學(xué)人氣:451 ℃時(shí)間:2020-05-13 16:06:28
    優(yōu)質(zhì)解答
    cos3π/11=cos(π-8π/11)=-cos8π/11; cos5π/11=-cos(π+5π/11)=-cos16π/11,
    所以cosπ/11*cos2π/11*cos3π/11*cos4π/11*cos5π/11
    =cosπ/11*cos2π/11*cos4π/11*cos8π/11*cos16π/11 =2sinπ/11*cosπ/11*cos2π/11*cos4π/11*cos8π/11*cos16π/11]/2sinπ/11
    =sin2pai/11*cos2π/11*cos4π/11*cos8π/11*cos16π/11]/2sinπ/11
    =sin4pai/11*cos4π/11*cos8π/11*cos16π/11]/4sinπ/11
    =sin8pai/11*cos8π/11*cos16π/11]/8sinπ/11
    =sin16pai/11*cos16π/11]/16sinπ/11=sin32pai/11]/32sinπ/11=sin10pai/11]/32sinπ/11=1/32
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