變成極坐標(biāo)
x=rcos(θ),y=rsin(θ)
r^2cos^2(θ) 4r^2sin^2(θ)=1
旋轉(zhuǎn)π/3即
r^2cos^2(θ π/3) 4r^2sin^2(θ π/3)=1
有公式
cos(a b)=cos(a)cos(b)-sin(a)sin(b)
sin(a b)=sin(a)cos(b) cos(a)sin(b)
帶回原式
r^2[cos(θ)cos(π/3)-sin(θ)sin(π/3)]^2 4r^2[sin(θ)cos(π/3) cos(θ)sin(π/3)]^2=1
[cos(π/3)x sin(π/3)y]^2 4[cos(π/3)y sin(π/3)x]^2=1
已知cos(π/3)=√3/2,sin(π/3)=1/2,
拆開(kāi)化簡(jiǎn)得7x^2 13y^2 5√3xy=4
我是用手機(jī)打的,出了點(diǎn)問(wèn)題,所有的空格都看成是加號(hào)好了
求曲線x^2+4y^2=1繞原點(diǎn)逆時(shí)針π/3所得的曲線方程
求曲線x^2+4y^2=1繞原點(diǎn)逆時(shí)針π/3所得的曲線方程
數(shù)學(xué)人氣:831 ℃時(shí)間:2020-04-29 23:07:34
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