是這么回事.solve函數(shù)求解方程組時(shí),函數(shù)輸出結(jié)果,也就是方程組的未知數(shù)是有一定順序的.你的例子一共有4個(gè)未知數(shù),solve求解出來(lái)后[x1,x2,x4,x4]存放的分別是t,x,y,z.如果你這么調(diào)用[t,x,y,z]=solve(2*x+3*y-z+t-2,5*x+y+z-t-13,x-y+2*z+2*t-3,3*x+2*y+2*z+9*t+3)
,t存放t,x存放x,y存放y,z存放z,當(dāng)然和實(shí)際結(jié)果一樣.
可是如果這樣[x,y,z,t]=solve(2*x+3*y-z+t-2,5*x+y+z-t-13,x-y+2*z+2*t-3,3*x+2*y+2*z+9*t+3),那么x存放的實(shí)際就是t了,y存放x等等
樓主說(shuō)對(duì)了,的確是按照英文字母的順序.以下是MATLAB中的幫助信息：
For a system of equations and an equal number of outputs,the results are sorted alphabetically and assigned to the outputs.
"alphabetically"就是按字母順序的意思