n(Al3+) = mg/27g/mol = 0.037mol
c(Al3+) = 0.037mol /VmL = 37/V mol/L
則原溶液中硫酸根的濃度為：c(SO42-) = 3/2 *c(Al3+)
取一半原溶液稀釋到3VmL,相當于把溶液稀釋6倍,所以得到的硫酸的濃度：
c(SO42-) = 3/2 *c(Al3+) * 1/6 = 3/2 * 37/V mol/L * 1/6 = 37/4V mol/L額。。選擇題里沒有這個選項。。A;250m/27vB;25om/9vc;500m/9vD;125m/9vn(Al3+) = mg/27g/mol = m/27 molc(Al3+) = m/17mol /VmL = 1000m/27v mol/L則原溶液中硫酸根的濃度為：c(SO42-) = 3/2 *c(Al3+)取一半原溶液稀釋到3VmL，相當于把溶液稀釋6倍，所以得到的硫酸的濃度：c(SO42-) = 3/2 *c(Al3+) * 1/6 = 3/2 * 1000m/27v mol/L * 1/6 = 250m/27v mol/L 上面把鋁離子的物質(zhì)的量算錯了，所以結(jié)果錯了。謝謝提醒！