1y'=a+(b/c)*(-1)/x^2 1/x=x^(-1) (1/x)'=(x^(-1))'=-x^(-2)=-1/x^22y'=1/(x(cosx)^2)-tanx/x^2 +cosx +(1/3)x^(-2/3)arctanx+x^(1/3)*(1/(1+x^2))tanx=1/cosx^2 (1/x)'=-1/x^2 (sinx)'=cosx ( x^(1/3))'=(1/3)x^(-2...不好意思啊 請(qǐng)問你這個(gè)是不是高等解法？我發(fā)現(xiàn)我看不懂。?？梢院?jiǎn)單詳細(xì)一點(diǎn)嗎 我數(shù)學(xué)真不好乘積的求導(dǎo)：（uv）'=u' v+uv’請(qǐng)對(duì)照教材好好學(xué)習(xí)1y'=a+(b/c)*(-1)/x^2公式：(x^n)'=nx^(n-1)1/x=x^(-1)(1/x)'=(x^(-1))'=-x^(-2)=-1/x^22y'=1/(x(cosx)^2)-tanx/x^2 +cosx +(1/3)x^(-2/3)arctanx+x^(1/3)*(1/(1+x^2))公式：tanx=1/cosx^2 (1/x)'=-1/x^2(sinx)'=cosx ( x^(1/3))'=(1/3)x^(-2/3)(arctanx)'=1/(1+x^2)3y'=2xlog<3> x+x^2*(1/ln3)*(1/x)公式：(lnx)'=1/x(x^2)'=2xlog<3>x=lnx/ln3(log<3>x)'=(1/ln3)(lnx)'=(1/ln3)(1/x)