先求x的定義域和y的值域
y=√(x^2-2x+3)=√[(x-1)^2+2]>=√2
所以x∈R,y>=√2
然后求反函數(shù)
y^2=(x-1)^2+2
(x-1)^2=y^2-2
x=±√(y^2-2)+1
再將x、y符號互換,并列出x的定義域,即得反函數(shù)
y=1±√(x^2-2) (x>=√2)
完畢!