如果cos2θ+2msinθ-2m-2＜0對(duì)任意的θ總成立，求常數(shù)m的取值范圍．
如果cos2θ+2msinθ-2m-2＜0對(duì)任意的θ總成立，求常數(shù)m的取值范圍．
數(shù)學(xué)人氣：960 ℃時(shí)間：2020-07-14 06:42:34
優(yōu)質(zhì)解答
設(shè)f（θ）=cos2θ+2msinθ-2m-2，要使f（θ）＜0對(duì)任意的θ總成立，當(dāng)且僅當(dāng)函數(shù)y=f（θ）的最大值小于零．f（θ）=cos2θ+2msinθ-2m-2=1-sin2θ+2msinθ-2m-2=-（sinθ-m）2+m2-2m-1∴當(dāng)-1≤m≤1時(shí)，函數(shù)的最大值...
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