d/dx ∫(1/x→√x) sin(t²) dt
= d(√x)/dx · sin(√x²) - d(1/x)/dx · sin(1/x²)
= 1/(2√x) · sin|x| - (- 1/x²) · sin(1/x²)
= (sinx)/(2√x) + [sin(1/x²)]/x²
求dy/dx,y=∫sin(t^2)dt由1/x積到根號(hào)x
求dy/dx,y=∫sin(t^2)dt由1/x積到根號(hào)x
數(shù)學(xué)人氣:347 ℃時(shí)間:2019-08-26 07:02:27
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