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| 2 |
| 1 |
| 4 |
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1?(
| ||
1?
|
| 1 |
| 2n?1 |
∴Sn＝2n?(1+
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| 2 |
| 1 |
| 22 |
| 1 |
| 2n?1 |
1?
| ||
1?
|
| 1 |
| 2n?1 |
求和：Sn=1+（1+1/2）+（1+1/2+1/4）+[1+1/2+1/4+…+（1/2）n-1]．
求和：Sn=1+（1+
）+（1+
+
）+[1+
+
+…+（
）n-1]．
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| 2 |
| 1 |
| 2 |
| 1 |
| 4 |
| 1 |
| 2 |
| 1 |
| 4 |
| 1 |
| 2 |
數(shù)學(xué)人氣：231 ℃時(shí)間：2020-03-20 22:14:41
優(yōu)質(zhì)解答
∵1+
+
+…+（
）n-1=
=2?
，
∴Sn＝2n?(1+
+
+…+
)=2n-
=2n-2+
．
∴Sn＝2n?(1+
我來回答
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