這道題目。已知y=√3sin(2x-φ)
請問φ怎么求?
由圖可知:函數(shù)初相為第三象限角,點(diǎn)(π/3,0),(5π/6,0)為函數(shù)的二個零點(diǎn),任選擇一個代入函數(shù)y=√3sin(2x-φ)==>0 =√3sin(2π/3-φ)==>2π/3-φ=2π==>φ=-4π/3∴y=√3sin(2x+4π/3)
這道題目。已知y=√3sin(2x-φ)
請問φ怎么求?
由圖可知:函數(shù)初相為第三象限角,點(diǎn)(π/3,0),(5π/6,0)為函數(shù)的二個零點(diǎn),任選擇一個代入函數(shù)y=√3sin(2x-φ)==>0 =√3sin(2π/3-φ)==>2π/3-φ=2π==>φ=-4π/3∴y=√3sin(2x+4π/3)