∫dx/(1-cosx)
=∫1/(2sin²(x/2))dx
=∫(csc²(x/2))d(x/2)
=-cot(x/2)+C
求不定積分∫dx/(1-cosx)
求不定積分∫dx/(1-cosx)
數(shù)學(xué)人氣：252 ℃時(shí)間：2020-02-06 07:56:09
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