(x的平方-5x+6)分之(x的平方-1)-(x-3)分之2x=(2-x)分之x
[ (x²-1) - 2x(x-2) ]/ [/(x-2)(x-3)]=x/(2-x)
x²-4x+1=x(x-3)
-4x+1=-3x
x=1化簡的呢(x的平方-5x+6)分之(x的平方-1)-(x-3)分之2x=(2-x)分之x (x²-1) /(x-2)(x-3) -2x/(x-3)= x/(2-x)[ (x²-1) - 2x(x-2) ]/ [(x-2)(x-3)]=x/(2-x)(-x²+4x-1)/ [(x-2)(x-3)]=x/(2-x)x²-4x+1=x(x-3)-4x+1=-3xx=1x的平方-y的平方分之x的平方+2xy+y的平方除以x-y分之x的平方+xy=(x+y)²/(x+y)(x-y) ÷ x(x+y)/(x-y)=(x+y)/(x-y) × (x-y)/x(x+y)=1/x