(x²-x-1)/(x²+x+1)≥0 解此不等式
解析：∵(x²-x-1)/(x²+x+1)≥0
x²+x+1>0==>x∈R
∴x²-x-1>=0
解得x<=(1-√5)/2或x>=(1+√5)/2
取二者交
∴原不等式的解集為x<=(1-√5)/2或x>=(1+√5)/2第三步有點(diǎn)沒有看懂能詳細(xì)解答一下嗎x∈R且（x<=(1-√5)/2或x>=(1+√5)/2）即x<=(1-√5)/2或x>=(1+√5)/2