設(shè)最后一個數(shù)為y,被去的數(shù)為x
則一共有y-11個數(shù),和為(y+12)(y-11)/2
去掉x后剩y-12個數(shù),和為(y+12)(y-11)/2-x
故 [ (y+12)(y-11)/2-x ]/(y-12)＝952/19
化簡得x=(y+12)(y-11)/2-952/19×(y-12)
又x,y∈N＋
所以設(shè)y-12=19n
根據(jù)x=(y+12)(y-11)/2-952/19×(y-12)
y-12=19n
12≦x≦y得3.958≦n≦4.063
所以n=4
則y=88
x=42