(1)反應(yīng)前n(H2SO4)=18.5*0.2=3.7mol,反應(yīng)后n(H2SO4)=0.2*1/2=0.1mol
所以參加反應(yīng)的硫酸的物質(zhì)的量=3.7-0.1=3.6mol
(2)開(kāi)始時(shí)因?yàn)槭菨饬蛩?生成的是SO2,.反應(yīng)一段時(shí)間后濃硫酸變稀,生成H2.
由已知有：n(SO2)+n(H2)=67.2/22.4=3mol
Zn + 2H2SO4(濃) == ZnSO4 + SO2↑ + 2H2O,Zn + H2SO4 == ZnSO4 + H2↑
所以有：n1(H2SO4) + n2(H2SO4) = 3.6mol
n1(H2SO4) = 2*n(SO2)
n2(H2SO4) = n(H2)
四個(gè)方程組解得n(SO2)=0.6mol,n(H2)=2.4mol
(3)氣體A各組分氣體的體積比是SO2:H2 = 1:4