答：1.原式=(2x-5)(2x²+5x-3)=(2x-5)(2x-1)(x+3)2.原式=3.原式=(x+3)(x²+3x+2)=(x+3)(x+2)(x+1)4.原式=(x-2)(x³+4x²-x-4)=(x-2)(x+1)(x²+3x-4)=(x-2)(x+1)(x+4)(x-1)5.原式=6.原式=(x+3)(x...那1.（x-2)³-（y-2)³-（x-y）³=2.ab（a+b）²-（a+b）²+1=3.9x²-6x-y²+4y-3=4.（x²+5x+20(x²+5x+3）-12=5.a²-b²+4a+2b+36.（x+y)(x+y+2xy）+（xy+1)(xy-1)回復(fù)：哇塞，加量記得加價(jià)??！1.原式=(x-2-y+2)[(x-2)²+(x-2)(y-2)+(y-2)²]-(x-y)(x-y)²=(x-y)[(x-2)²+(x-2)(y-2)+(y-2)²-(x-y)²]=(x-y)(x²-4x+4+xy-2x-2y+4+y²-4y+4-x²-y²+2xy)=(x-y)(-6x+3xy-6y+12)=3(x-y)(xy-2x-2y+4)=3(x-y)(x-2)(y-2)2.原式=3.原式=9x²-6x+1-y²+4y-4=(3x-1)²-(y-2)²=(3x-1+y-2)(3x-1-y+2)=(3x+y-3)(3x-y+1)4.原式=(x²+5x)²+5(x²+5x)+6-12=(x²+5x)²+5(x²+5x)-6=(x²+5x+6)(x²+5x-1)=(x+2)(x+3)(x²+5x-1)5.原式=a²+4a+4-b²+2b-1=(a+2)²-(b-1)²=(a+2+b-1)(a+2-b+1)=(a+b+1)(a-b+3)6.原式=