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  • 20道化簡(jiǎn)求值題 7年級(jí)上 帶過程 帶答案 跪求

    20道化簡(jiǎn)求值題 7年級(jí)上 帶過程 帶答案 跪求
    謝謝
    數(shù)學(xué)人氣:591 ℃時(shí)間:2020-05-30 20:39:21
    優(yōu)質(zhì)解答
    1,3x'y-[2x'y-(2xyz-x'z)-4x'z]-xyz,其中x=-2,y=-3,z=1,
    原式=3x'y-[2x'y-(2xyz-x'z)-4x'z]-xyz
    =3x'y-2x'y+2xyz-x'z+4x'z-xyz
    =x'y-xyz+3x'z
    當(dāng)x=2,y=3,z=1時(shí)
    原式=4*(-3)-2*3*1+3*4*1
    =-12-6+12
    =-6
    2,3X+2Y)+(4X+3Y)其中X=5,Y+3
    原式=3X+2Y+4X+3Y=7X+5Y
    當(dāng)X=5,Y=3時(shí)
    原式=5*7+(-3)*5+20
    =35-15+20
    =40
    3,2x-3(2x-x)+(2y-y),其中x=1,y=2
    解;原式=2x-3x+y
    當(dāng)x=1,y=2時(shí)
    原式=2*1-3*1+2
    =2-3+2
    =1
    4,(5a^2-3b^2)+(a^2+b^2)-(5a^2+3b^2),其中a=-1,b=1
    =5a^2-3b^2+a^2+b^2-5a^2-3b^2
    =a^2-5b^2
    =(-1)^2-5*1^2
    =1-5
    =-4
    5,2(a^2b+ab^2)-2(a^2 b-1)-2ab^2 -2其中a=-2,b=2
    =2a^2b+2ab^2-2a^2b+2-2ab^2-2
    =0,
    6,a^2-ab+2b^2=3 求2ab-2a^2-4b^2-7的值
    2ab-2a^2-4b^2-7
    =2(ab-a^2-2b^2)-7
    =-2(a^2-ab+2b^2)-7
    =(-2)*3-7
    =-6-7
    =-13
    7,若A=2x^2+3xy-2x-3,B=-x^2+xy+2,且3A+6B的值與x無關(guān),求y的值
    3A+6B=6x^2+9xy-6x-9-6x^2+6xy+12
    =15xy-6x+3
    =x(15y-6)+3
    8,x+6x^2 -3(x-2/3x^2).其中x=-2
    9x+6x² -3(x-2/3x²)
    =9x+6x²-3x+2x²
    =8x²+6x
    =8×(-2)²+6×(-2)
    =32-12
    =20
    9,1/4(-4x^2+2x-8)-(1/2x-1),其中x=1/2
    1/4(-4x²+2x-8)-(1/2x-1)
    =-x²+1/2x-2-1/2x+1
    =-x²-1
    =-(1/2)²-1
    =-1/4-1
    =-5/4,
    10,3x'y-[2x'y-(2xyz-x'z)-4x'z]-xyz,其中x=-2,y=-3,z=1,
    :3x'y-[2x'y-(2xyz-x'z)-4x'z]-xyz
    =3x'y-2x'y+2xyz-x'z+4x'z-xyz
    =x'y-xyz+3x'z
    =4*(-3)-2*3*1+3*4*1
    =-12-6+12
    =-6
    11,(5a^2-3b^2)+(a^2+b^2)-(5a^2+3b^2),其中a=-1,b=1
    =5a^2-3b^2+a^2+b^2-5a^2-3b^2
    =a^2-5b^2
    =(-1)^2-5*1^2
    =1-5
    =-4
    12、2(a^2b+ab^2)-2(a^2 b-1)-2ab^2 -2其中a=-2,b=2
    =2a^2b+2ab^2-2a^2b+2-2ab^2-2
    =0
    13、(X-2分之1Y-1)(X-2分之1Y+1)-(X-2分之1Y-1)的平方,其中X=1.7,Y=3.9
    [(X-2分之1Y)-1][(X+2分之1Y)+1]-(X-2分之1Y-1)平方
    =(X+2分之1Y)平方-1-(X-2分之1Y)平方+2(X-2分之1Y)-1
    =(X+2分之1Y)平方-(X-2分之1Y)平方+2(X-2分之1Y)-2
    =2XY+2X-Y-2
    =3.9*2.4+1.4
    =10.76
    14,2a-(3a-2b+2)+(3a-4b-1),其中a=5 b=-3
    =2a-3a+2b-2+3a-4b-1
    =(2-3+3)a+(2-4)b+(-2-1)
    =2a-2b-3
    =10-(-6)-3
    =10+6-3
    =13
    15,5-(1-x)-1-(x-1)-2x+(-5y),其中x=2,y=2x
    =4-2x-5y
    =4-4-20
    =-20
    16,2x-(x+3y)-(-x-y)-(x-y),其中x=3,y=-3
    =2x-x+3y+x+y-x+y
    =x+5y
    =3-15
    =-12
    17,-ab+3ba-(-2ab),其中a=2,b=1
    =-ab+3ba+2ab
    =2ab+2ab
    =4ab
    =4*2*1
    =8
    18,-m-[-(2m-3n)]+[-(-3m)-4n],其中m=2,n=1
    =-m-(-2m+3n)+3m-4n
    =-m-4m+2m-3n+3m
    =-3n
    =-3*1
    =-3
    19,2(2a+2ab)-2(2ab-1)-2ab-2,其中a=-2 b=2
    =4a+4ab-4ab+2-2ab-2
    =4a-2ab
    =4*(-2)-2*(-2)*2
    =-8-(-8)
    =8+8
    =0
    20,3ab-4ab+8ab-7ab+ab,其中a=-2,b=3
    =-8ab+9ab
    =ab
    =-2*3
    =-6
    俄滴腎.終于完了.
    這可是我到處在我以前練習(xí)冊(cè)上找的,花了好長(zhǎng)時(shí)間呢~
    如果可以,把我的答案,
    我來回答
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