=-[ysin(xy)+2e^(2x+y)]/[ysin(xy)+e^(2x+y)]*(dx)麻煩給我寫出解的過程。。等式兩邊取對(duì)數(shù)，得：d[e^(2x+y)]-d[cos(xy)]=0(常數(shù)的導(dǎo)數(shù)為"0”)復(fù)合函數(shù)求導(dǎo)數(shù)，指數(shù)函數(shù)的導(dǎo)數(shù)d[e^(2x+y)]=[e^(2x+y)]*d(2*x+y)=2e^(2x+y)dx+e^(2x+y)dy；復(fù)合函數(shù)求導(dǎo)數(shù)，三角函數(shù)的導(dǎo)數(shù)d[cos(xy)]=-sin(xy)*d(xy)=-ysin(xy)*dx-xsin(xy)dy；合并同類項(xiàng)，整理即可得到答案，之前給出的答案好像寫錯(cuò)了個(gè)字母，自己理一遍。類似的題都可以這樣做，一步一步地進(jìn)行！