由題意得
AB=DE=7
BC=EF=10
可得
AC=DF=30-(7+10)=13
已知△ABC≌△DEF,AB和DE,BC和EF是對(duì)應(yīng)邊,△DEF的周長(zhǎng)是30cm,DE=7cm,EF=10cm,求AC的長(zhǎng)
已知△ABC≌△DEF,AB和DE,BC和EF是對(duì)應(yīng)邊,△DEF的周長(zhǎng)是30cm,DE=7cm,EF=10cm,求AC的長(zhǎng)
數(shù)學(xué)人氣:829 ℃時(shí)間:2019-08-21 14:55:34
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