一般來(lái)說(shuō),我們做f(x)展開(kāi)成x的冪級(jí)數(shù).所以我們要做該轉(zhuǎn)換.首先,設(shè)u=(x-1)/(x+1) => x=(1+u)/(1-u)那么題目等同于將ln((1+u)/(1-u))展開(kāi)成u的冪級(jí)數(shù)那么ln((1+u)/(1-u))=ln(1+u)-ln(1+(-u))參照上一問(wèn)題,樓主應(yīng)該知道...