這個問題是這樣的
4=2²=（2^3）^(2/3)=8^(2/3)
所以 log8( 8^(2/3))=2/3
前面的是對數(shù)運算法則 loga M-loga N=loga (M/N)
log4(3)-log4(12)-log8(4) =log4(3/12)- log8( 8^(2/3) ) log8( 8^(2/3) )怎么得出來的?
log4(3)-log4(12)-log8(4) =log4(3/12)- log8( 8^(2/3) ) log8( 8^(2/3) )怎么得出來的?
數(shù)學人氣：546 ℃時間：2020-05-29 07:14:24
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