tan(a b)=4,cot(a-b)=-3,求tan2a和tan2b
tan(a b)=4,cot(a-b)=-3,求tan2a和tan2b
數(shù)學(xué)人氣：311 ℃時間：2020-09-20 04:25:34
優(yōu)質(zhì)解答
tan(a+ b)=4,cot(a-b)=-3,→tan(a- b)=-1/3(1).tan2a=tan[(a+ b)+(a-b)]=[tan(a+b)+tan(a- b)]/[1-tan(a +b)tan(a- b)]=[4-1/3]/[1-4*(-1/3)=(11/3)/(7/3)=11/7(2).tan2b=tan[(a+ b)-(a-b)]=[tan(a+b)-tan(a- b)]/[1...
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