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  • 北大師版七年級上冊數(shù)學(xué)加減整式數(shù)學(xué)題(只要計(jì)算題)速度!很急!

    北大師版七年級上冊數(shù)學(xué)加減整式數(shù)學(xué)題(只要計(jì)算題)速度!很急!
    數(shù)學(xué)人氣:736 ℃時間:2020-05-23 16:53:15
    優(yōu)質(zhì)解答
    (2x-3y)+(5x+4y)
    (8a-7b)-(4a-5b)
    -(3x-2y + z)-[5x-(x-2y +z ) -3x]
    2(7x2+5x-3)-3(5x2-3x+2)
    2b3 +(3ab3-a2b)-2(ab2 + b3)
    (-6x2+5xy)-12xy-(2x2-9xy)
    (x2-2x3 +1)-(-1+2x3 + 2x2),其中x=2
    3a-[-2b+(4a-3b)],其中a=-1,b=3
    3ab-4ab+8ab-7ab+ab=
    7x-(5x-5y)-y=
    23a3bc2-15ab2c+8abc-24a3bc2-8abc=
    -7x2+6x+13x2-4x-5x2=
    2y+(-2y+5)-(3y+2)=
    (2x2-3xy+4y2)+(x2+2xy-3y2)=
    2a-(3a-2b+2)+(3a-4b-1)=
    -6x2-7x2+15x2-2x2=
    2x-(x+3y)-(-x-y)-(x-y)=
    2x+2y-[3x-2(x-y)]=
    5-(1-x)-1-(x-1)=
    已知A=x3-2x2+x-4,B=2x3-5x+3,計(jì)算A+B=
    若a=-0.2,b=0.5,代數(shù)式-(|a2b|-|ab2|)的值為
    -(2x2-y2)-[2y2-(x2+2xy)]=
    (-y+6+3y4-y3)-(2y2-3y3+y4-7)=
    4x2-[7x2-5x-3(1-2x+x2)]=
    3a-(2a-3b)+3(a-2b)-b=
    x-[y-2x-(x+y)] =
    3x-[y-(2x+y)]=
    4a2n-an-(3an-2a2n)=
    2x2y+3xy2-x2+2xy=
    -5xm-xm-(-7xm)+(-3xm)=
    當(dāng)a=-1,b=-2時,
    [a-(b-c)]-[-b-(-c-a)]=
    當(dāng)a=-1,b=1,c=-1時,
    -[b-2(-5a)]-(-3b+5c)=
    -2(3x+z)-(-6x)+(-5y+3z)=
    -5an-an+1-(-7an+1)+(-3an)=
    3a-(2a-4b-6c)+3(-2c+2b)=
    9a2+[7a2-2a-(-a2+3a)]=
    當(dāng)2y-x=5時,5(x-2y)2-3(-x+2y)-100=
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