根據(jù)x^2+(x^2-1)^2=(x^2+1)^2 x為奇數(shù)
所以三條邊長(zhǎng)15 112 113
s=15*112/2=840“根據(jù)x^2+(x^2-1)^2=(x^2+1)^2x為奇數(shù)”這個(gè)是怎么來(lái)的呀？？不好意思是x^2+[(x^2-1)/2]^2=[(x^2+1)/2]^2這是一推論假定a為大于0的任意整數(shù)[(x^2+1)/2]^2-[(x^2-1)/2]^2=(x^4+2x^2+1-x^4+2x^2-1)/4=x^2