y'=7cos7x+14sin7xcos7x
y'(0)=7
切線為y=7x
Find an equation of the tangent line to the curve at the given point.y = sin 7x + sin2 7x,(0,0)
Find an equation of the tangent line to the curve at the given point.y = sin 7x + sin2 7x,(0,0)
y = sin(7x) + sin^2(7x),(0,0)求方程在（0,0）點的切線方程
y=
y = sin(7x) + sin^2(7x),(0,0)求方程在（0,0）點的切線方程
y=
數(shù)學(xué)人氣：688 ℃時間：2020-04-23 03:03:25
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