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  • 求式子I1/3-1/2I+I1/4-1/3I+I1/5-1/4I+.+I1/10-1/9I=

    求式子I1/3-1/2I+I1/4-1/3I+I1/5-1/4I+.+I1/10-1/9I=
    I1/5-150/559I+I150/559-1/3I-I-1/3I用合理的方法算
    數(shù)學(xué)人氣:432 ℃時(shí)間:2020-06-26 14:08:43
    優(yōu)質(zhì)解答
    I1/3-1/2I+I1/4-1/3I+I1/5-1/4I+.+I1/10-1/9I
    =1/2-1/3+1/3-1/4+1/4-1/5+……+1/9-1/10
    =1/2-1/10
    =2/5I1/5-150/559I+I150/559-1/3I-I-1/3I用合理的方法算I1/5-150/559I+I150/559-1/3I-I-1/3I=150/559-1/5+1/3-150/559-1/3=-1/5若實(shí)數(shù)a、b滿足a/IaI+b/IbI=0,則ab/IabI=1/6+1/12+1/20+1/30+1/42+1/56=若實(shí)數(shù)a、b滿足a/IaI+b/IbI=0,a+b=0a=-b則ab/IabI=-11/6+1/12+1/20+1/30+1/42+1/56=1/2-1/3+1/3-1/4+1/4-1/5+1/5-1/6+1/6-1/7+1/7-1/8=1/2-1/8=3/8若實(shí)數(shù)a、b滿足a/IaI+b/IbI=0,a+b=0a=-b則ab/IabI=-11/6+1/12+1/20+1/30+1/42+1/56=1/2-1/3+1/3-1/4+1/4-1/5+1/5-1/6+1/6-1/7+1/7-1/8=1/2-1/8=3/8若a=2004/2003,b=2003/2002,c=2002/2001,則a、b、c的關(guān)系是用>符號(hào)連接a=2004/2003,b=2003/2002,c=2002/2001,a
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