1/a+1/b=3
(a+b)/ab=3
a+b=3ab
原式=[(a+b)-2ab]/[2(a+b)+ab]
=[(3ab)-2ab]/[2(3ab)+ab]
=ab/7ab
=1/7
已知1/a+1/b=3,求(a-2ab+b)/(2ab+ab+2b)的值
已知1/a+1/b=3,求(a-2ab+b)/(2ab+ab+2b)的值
數(shù)學(xué)人氣：697 ℃時(shí)間：2020-02-06 00:41:26
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