y=sin(2x-π/3)+根號3 cos2x
=sin2xcosπ/3-cos2xsinπ/3+2sinπ/3 cos2x
=sin2xcosπ/3+cos2xsinπ/3
=sin(2x+π/3)
1.振幅=1
2、周期=2π/2=π
3、函數(shù)的圖像可以由y=sinx(x∈R）的圖像經(jīng)過橫向縮小1/2,再向左移動π/6得到過程可不可以詳細點，另外第二問的圖怎么畫？y=sin(2x-π/3)+根號3 cos2x=sin2xcosπ/3-cos2xsinπ/3+2sinπ/3 cos2x=sin2xcosπ/3+cos2xsinπ/3=sin(2x+π/3)1.振幅就是這個三角函數(shù)前面的系數(shù)，=12.畫圖。y=sin(2x+π/3)=sin(2(x+π/6))由此可看出它的周期是2π/2=π。只不過在x軸上，它是以-π/6為中心的，分別從(-π/6,0)，(0,根號3/2)，π/6，π/3，π/2，2π/3, 5π/6畫點，一個周期。